# Find the sum of all the three digit number divisible by 4

2
by teena3

• qais
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2016-03-29T13:47:28+05:30

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Three digit numbers are from 100 to 999
divisible by 4 = 100, 104, 108.......996
so, this is an AP with first term 100 and common difference = 4
To find number of terms
996 = [100+(n-1)4]
⇒4n -4 = 896
⇒4n = 900
⇒n = 225
now, sum = (225/2)[100+996] = (225×1096)/2
= 123300
2016-03-29T14:20:05+05:30
Three digit numbers are from 100 to 999
divisible by 4 = 100, 104, 108.......996
so, this is an AP with first term 100 and common difference = 4
To find number of terms
996 = [100+(n-1)4]
=4n -4 = 896
=4n = 900
=n = 225
now, sum = (225/2)[100+996] = (225×1096)/2
= 123300