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2016-04-13T00:01:56+05:30

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Given:
Perimeter of a rhombus = 52 cm
one diagonal = 24 cm

find length of its other diagonal and its area.

Area = pq/2 where p and q are diagonals.

Area = 1/4 p √P² - 4p²
Area = 1/4 24cm √(52cm)² - 4 (24cm)²
Area = 6cm √2704cm² - 2304cm²
Area = 6cm √400cm²
Area = 6cm * 20cm
Area = 120cm²

Area = pq/2
120cm
² = (24cm * q)/2
240cm² = 24cm * q
240cm² / 24 cm = q
10cm = q
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