# The perimeter of a rhombus is 52 ccm . if one diagonal is 24 cm ; find the lenght of its other diagonal and its area

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Given:

Perimeter of a rhombus = 52 cm

one diagonal = 24 cm

find length of its other diagonal and its area.

Area = pq/2 where p and q are diagonals.

Area = 1/4 p √P² - 4p²

Area = 1/4 24cm √(52cm)² - 4 (24cm)²

Area = 6cm √2704cm² - 2304cm²

Area = 6cm √400cm²

Area = 6cm * 20cm

**Area = 120cm²**

Area = pq/2

120cm² = (24cm * q)/2

240cm² = 24cm * q

240cm² / 24 cm = q

**10cm = q**

Perimeter of a rhombus = 52 cm

one diagonal = 24 cm

find length of its other diagonal and its area.

Area = pq/2 where p and q are diagonals.

Area = 1/4 p √P² - 4p²

Area = 1/4 24cm √(52cm)² - 4 (24cm)²

Area = 6cm √2704cm² - 2304cm²

Area = 6cm √400cm²

Area = 6cm * 20cm

Area = pq/2

120cm

240cm² = 24cm * q

240cm² / 24 cm = q