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## Answers

Product of the three numbers is 343.

a÷r × a × ar =343

a3 = 343

a = 3√343

a = 7

Sum of the three numbers is 57

a÷r + a + ar = 57

a[1÷r + 1 + r]= 57

7(1÷r + r÷r + r2÷r)= 57

7+7r+7r2 =57r

7r2-50r+7=0

(r-7)(7r-1)=0

r=7 (or) r=1\7

Case 1:

If r=1\7,the three numbers are,

7(7), 7, 7(1\7)

49, 7 , 1.

Case 2:

If r= 7,the three numbers are,

7(1\7), 7, 7(7)

1, 7, 49.