Answers

2016-04-04T22:09:04+05:30
4x^2 + 3x + 7 = 0
it dont have roots and it can't be factorised...
because when we apply formula
D = b^2- 4ac
to it then the value of D comes In negative...it means it dont have real roots..
4x^2 + 3x + 7..
now in the equation...
a = 4
b = 3
c = 7..
the equation becomes..
D = (3)^2 - 4(4)(7)
D = 9 - 112
D = -103..
now here D is negative so it can't be factorised and also it don't have real roots...
0
hope it helped...
please mark it as brainliest..
2016-04-04T22:33:34+05:30
Eq--------4x^2 +3x+7........... Comparing it with ax^2+bx+c....... a= 4, b= 3, c= 7............... D= b^2-4ac...... = (3)^2-4×4×7...........= 9-112............ = -103. Since D<0 , Therefore no real roots exist for this equation.
1 5 1