# A 3000kg truck moving at speed of 72km/h stops after covering some distance.The force applied by brakes is 24000N. Compute the distance covered and work done by this force.

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so 24000N =3000kg ×a

so acceleration=24000÷3000 =8m/s2

now speed(v)=72km/h=4m/s

now we know :

v2= u2 +2as

so 4×4=0+2 ×8×s

16=0+16s

so s=1metre

now work done =fs

=24000N×1m

=24000joules