# Force acting on a particle is 5N. If the unit of length and time are doubled and the unit of mass is halved, the find the numerical value of the force in the new unit.

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by hazelreeva

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by hazelreeva

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F = m×a

F = M × L/T²

length and time are doubled

mass is halved

let the new force = Fₓ

Fₓ = M/2 × 2L/4T²

Fₓ = M × L/4T²

new force(Fₓ) = F/4

Numerical value of new force = 5/4 N