Answers

2016-04-06T12:42:18+05:30
Given weights of flour = 4.97 , 5.05 , 5.08 , 5.03 , 5.00 , 5.06 , 5.08 , 5.04 , 5.00 , 4.98
n(S) = 10
Let (E) be the event of getting a bag with more than 5kg flour
n(E) = 6
P(E) = n(E)/n(S) = 6/10 = 3/5
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2016-04-06T14:04:13+05:30
Total number of bags = 10
No.bags contains more than 5 kg of flour = 6
Probability that bag chosen at random contains more than 5 kg of flour = No.bags contains more than 5 kg of flour / Total number of bags 
= 6/10
=3/5
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