Answers

2016-04-06T21:24:58+05:30
Sec A + tan A = 1/3
sec A - tan A = (?)

Now,
sec² A - tan² A = 1
∴(sec A + tan A) (sec A - tan A) = 1   [∵a² - b² = (a+b)(a-b) ]
∴1/3 *(sec A - tan A) = 1
∴sec A - tan A = 1* 3
sec A - tan A = 3
1 2 1
2016-04-06T22:37:30+05:30
Sec A + tan A = 1/3
sec A - tan A = unknown

So,
sec² A - tan² A = 1
∴  (sec A + tan A) (sec A - tan A) = 1 
∴  1/3 *(sec A - tan A) = 1

∴  sec A - tan A = 3
1 5 1