Answers

2016-04-07T19:17:04+05:30
PH = - logH⁺
      = -log0.004
      = -log4 ×10⁻³
      = 3 - log4
      = 3 - 2log2
      = 3 - 2(0.3)
      = 3- 0.6
PH = 2.4
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  • qais
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2016-04-08T09:13:47+05:30
PH = 14 - pOH
pOH = -Log[OH-]
        =- Log[0.004] = -Log[4×10^(-3)]
        = -Log4 - Log[10^(-3)] = -Log[2²] - Log[10^(-3)] 
        = -2 Log2 +3
Log2 = 0.301
pOH = -2
×0.301 +3 = -0.602 +3 = 2.398
now, pH = 14 - 2.398 = 11.602
Note that, pH of base should be greater than 7 but less than 14.
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