Answers

2014-08-09T21:46:57+05:30
First of all find the equation of normal to curve at (1, 0)

y = log_ex \\  \frac{dy}{dx} =  \frac{1}{x} \\  (\frac{dy}{dx})_(_x _= _1_, _y _= _0_) = 1

This is slope of tangent so slope of normal is -1.
So equation of line -> (y - 0) = (-1) * (x - 1) -> x + y = 1

This is the line intersection x-axis at (1, 0) and y-axis at (0, 1), forming a right angle triangle with height = 1 unit and base = 1 unit.

So area = \frac{1}{2} * 1 * 1

Answer
(c)
1 5 1
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