Log in to add a comment

## Answers

The Brainliest Answer!

A = {even numbers} = { 26,28,30,32,34,36,38,40,42,44}

B = {multiples of 3} = { 27,30,33,36,39,42}

i)n(A) + n(B) = 10 + 6 = 16

ii) n(AUB) = n[{26,27,28,30,32,33,34,36,38,39,40,42,44}]

= 13

n(A∩B) = n[{30,36,42}]

= 3

n(AUB) + n(A∩B) = 16

iii) A-B = { 26,28,32,34,38,40,44}

n(A-B) = 7

no. of numbers b/w 25 and 45 = 18

no .of even numbers are= 9

no.of multiples of 3 are = 6

there fore n(A) +n(B) = 9+6 = 15

(ii) n(A U B) + n( A ∩ B) :

A = 26, 28,30,32,34,36,38,40,42,44

B = 27,30,33,36,39,42,

A U B = 26,27,28,30,32,33,34,36,38,39,40,42,44

n( A U B) = 13

A ∩B = 30,36,42

n(A U B) =3

therefore n(AUB) + n(A ∩ B) = 13 + 3 =16

(iii) n( A - B) :

A -B = 26,28,32,34,38,40,44

n( A -B) =7