can anyone help me

I am doing

Just facing some network issues

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can anyone help me

I am doing

Just facing some network issues

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2 integer 1/2 = 5/2

1 integer 2/3 = 5/3

1 integer 3/4 = 7/4

Let the three parts of 4260 be 5x/2, 5x/3 and 7x/4

So, 5x/2 + 5x/3 + 7x/4 = 4260

LCM = 12 (Multiplying 12 on both sides)

∴ 5x/2 * 12 + 5x/3 * 12 + 7x/4 * 12 = 4260 * 12

∴5x * 6 + 5x * 4 + 7x * 3 = 51120

∴30x + 20x + 21x = 51120

∴71x = 51120

∴

So, the first part = 5x/2 = 5*720/2 = 5*360 = Rs. 1800

The second part = 5x/3 = 5*720/3 = 5*240 = Rs. 1200

The third part = 7x/4 = 7*720/4 = 7*180 = Rs. 1260