Answers

2016-04-11T11:31:38+05:30
When the stone at the height then it will have potential energy =mgh
as there is initial velocity =0
then kinetic enenrgy at h=0
if we drop the stone it acquires acceleration g.
we know that v square -u square =2as
v square=2gh
then final velocity v=root over 2gh
then kinetic energy=1/2mvsquare=gh
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