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The Brainliest Answer!
2016-04-11T18:02:38+05:30
Given,
x²+y²=6xy.......(1)
We know that (x+y)
² = x²+y²+2xy    ⇒ x²+y² = (x+y)²-2xy..............(2)
                        
(x-y)² = x²+y²-2xy      ⇒ x²+y² = (x-y)²+2xy ..............(3)
From (1) , (2) and (3)
(x+y)²-2xy = 6xy
(x+y)² = 8xy
x+y = 2 \sqrt{2xy}

(x-y)²+2xy = 6xy
(x-y)² = 4xy
x-y = 2 \sqrt{xy}

 \frac{x+y}{x-y} = 2 \sqrt{2xy} / 2 \sqrt{xy}
 \frac{x+y}{x-y}  \frac{1}{ \sqrt{2} }

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