Answers

2016-04-11T23:04:55+05:30
Since the objects are released from some height, they are in free fall and perform uniformly accelerated motion
where gravitational acceleration, g = 9.8m/s²

Let the two objects be A and B.

Let the object A be released at t = 0 s
Initial velocity, u = 0m/s
Time, t₁ = 2 s

∴Distance travelled, h₁ = 1/2 gt₁²
                                    = 1/2*9.8 * 2²
                                    = 9.8 * 2
                                    = 19.6 m
                               

Object B is released at t₂ = 1 s
Initial velocity, u = 0m/s
Time, t₃ = 2-1 = 1s
Distance travelled, h₂ =1/2 gt₃²                                  = 1/2 * g * 1²
                                  = 1/2 * 9.8 * 1
                                  = 9.8/2
                                  = 4.9 m

Thus, distance between object A and B = 19.6 - 4.9
                                                                = 14.7 m
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