# The hcf of two numbers is 23 and their lcm is 1449. if one of the numbers is 161

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LCM = 1449

Let the two numbers be a and b. Let a = 161. We have to find b.

We know that

HCF(a,b) * LCM(a,b) = a*b

∴23 * 1449 = 161 * b

∴23*1449/161 = b

∴b = 23*9

∴b = 207

Thus, the other number is

One of the two number is 161.

HCF of two number = 23

LCM of two number = 1449

Let second number = M

HCF × LCM = 161 × M

M = 23 × 1449 / 161

M = 207