Answers

2016-04-11T23:44:02+05:30
HCF = 23
LCM = 1449

Let the two numbers be a and b. Let a = 161. We have to find b.

We know that

HCF(a,b) * LCM(a,b) = a*b
∴23 * 1449 = 161 * b
∴23*1449/161 = b
∴b = 23*9
∴b = 207

Thus, the other number is 207.

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2016-04-12T10:57:14+05:30
Given,
One of the two number is 161.
HCF of two number = 23
LCM of two number = 1449
Let second number = M
HCF × LCM = 161 × M
M = 23 × 1449 / 161
M = 207
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