Answers

2016-04-12T16:37:10+05:30
log{{x+y}/3}=1/2{logx+log Y}
log(x+y) - log(3) = 1/2(log xy)
log(xy) - log(2)=1/2(log xy)
2xy-4=xy
xy=4

x/y + y/x =(x^2 + y^2) / xy = (x^2 + y^2) / 4

(4, 1) and (2,2) are factors of 4
# (16 + 1) / 4 = 17/4
# (4 + 4) / 4 = 2

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