Answers

2014-08-10T12:52:56+05:30
Digit at unit place is x, let digit at tens place is y, then-
x:y = 3:2
or \frac{x}{y} =  \frac{3}{2} -> 2 * x = 3 * y ......eq(1)

The original number is (10 * y + x)
If we reverse the digits get reversed so new number is (10 * x + y)

Now according to the question, (10 * x + y) = (10 * y + x) + 27
-> 9 * x - 9 * y = 27
-> 9 * (x - y) = 27
-> x - y = 3
-> y = x - 3 .......eq(2)

Now substitute value of y from eq(2) to eq(1)
-> 2 * x = 3 * (x - 3)
-> 2 * x = 3 * x - 9
-> x = 9

and y = x - 3 -> y = 6

So the number = (10 * y + x) -> 69

Answer
69
0
2014-08-10T17:10:00+05:30
Units place=x
tens place= 2/3 x
number value= 10* 2/3 x + x
                   =23/3 x
reverse number value= 10x + 2/3x
                              = 32/3 x
32/3x -23/3x =27
3x=27          x=9
 The number is 69
0