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## Answers

Sec^20-tan^20=1;

(seco+tan0)(sec0-tan0)=1;

1/3(sec0-tan0)=1;

sec0-tan0=3;

(seco+tan0)(sec0-tan0)=1;

1/3(sec0-tan0)=1;

sec0-tan0=3;

Sec²θ-tan²θ= 1

(secθ+tanθ)(secθ-tanθ)=1

given,

secθ+tanθ=1/3

so, secθ-tanθ=3

(secθ+tanθ)(secθ-tanθ)=1

given,

secθ+tanθ=1/3

so, secθ-tanθ=3