Answers

2016-04-12T18:26:52+05:30
Sec^20-tan^20=1;
(seco+tan0)(sec0-tan0)=1;
1/3(sec0-tan0)=1;
sec0-tan0=3;
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2016-04-12T18:31:38+05:30
Sec²θ-tan²θ= 1
(secθ+tanθ)(secθ-tanθ)=1
given,
secθ+tanθ=1/3
so, secθ-tanθ=3
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