Answers

2016-04-12T22:29:03+05:30
SEC² A -TAN²A  =1 
(SEC A-TAN A) (SEC A +TAN A)=1
GIVEN: 
 SEC A + TAN A  = 1/3
  SEC A - TAN A = 3
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2016-04-12T22:56:31+05:30
Sec A + tan A = 1/3
sec A - tan A = (?)

We know that,

sec² A - tan² A = 1
∴(sec A + tan A)(sec A - tan A) = 1
∴1/3 * (sec A -tan A) = 1                (Given)
sec A - tan A = 3
0