Answers

2016-04-12T23:16:35+05:30
For the given sound wave,

velocity, v = 340 m/s
wavelength, λ = 1.5 cm = 0.15 m
frequency, f = (?)

We know that

v = λf
∴340 = 0.15 * f
∴f = 340/0.15
f ≈ 2266.67 Hz

Now, the range of audible sound is 20 Hz to 20,000 Hz.

Also, as 2266.67 Hz is more than 20 Hz and less than 20 kHz, the sound wave is audible.
0