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2014-08-10T17:40:11+05:30

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R² = 5² + 10²  + 2 *5* 10 cos 30
   = 125 + 50 √3 
R = 211.6 N

Direction    tan α = Q sin 30 / ( P + Q cos 30)
                         = 10 * 0.5 / (5 + 10 √3/2)  =>    α = 20.1 deg

  R makes  α = 20.1 degrees with the line of force 5 N, towards the 10 N force.
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