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2014-08-10T16:38:32+05:30

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P = 110 Watts    V = 220 Volts RMS            P = V²/R
Resistance of bulb is R = V² / P = 220²/110  = 440 Ohms

Power consumed at V = 110 Volts RMS  :
   V² / R  = 110² / 440  = 27.5 Watts

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  • Brainly User
2014-08-10T16:48:58+05:30
P=v^2/R
 p=220x220/R
R=484
 now v=110 volts, R=484
p=v^2/R=110x110/484= 25watt
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