Answers

2014-08-10T17:03:00+05:30
y =  \sqrt{x}  \\  \\ y =  x^{ \frac{1}{2} }  \\  \\  \frac{dy}{dx} =  \frac{1}{2} *  x^{ \frac{1}{2} - 1} \\  \\  \frac{dy}{dx} =  \frac{1}{2} *  x^{ -\frac{1}{2}}   \\  \\  \frac{dy}{dx} =  \frac{1}{2 \sqrt{x} }
0
the required answer is dx/dy and not dy/dx
2014-08-10T17:21:13+05:30
Y= √x
x= y²
dx/dy = 2y or 2√x
0