Lets say

**velocity of wind is V** and

**with the wind jet takes T hrs.** then

**against the wind it will take (T + 1.6) hrs.**Also

**with the wind equivalent velocity will be (610 + V) miles/hr** and

**against the wind equivalent velocity will be (610 - V)**So,

**(610 + V) * (T) = 3660 .....(1)****(610 - V) * (T + 1.6) = 3660 .....(2)**From (1) and (2)

**(610 + V) * (T) = (610 - V) * (T + 1.6)****610T + VT = 610T - VT + 976 - 1.6V****VT = -VT + 976 - 1.6V****2VT = 976 - 1.6V****VT = 488 - 0.8V ......(3)**Rewrite (1)

610T + VT = 3660

Substitute VT from (3)

**610T + 488 - 0.8V = 3660****610T - 0.8V = 3172****305T - 0.4V = 1586****305T = 1586 + 0.4V .....(4)**Multiply by 305 in (1)

(610 + V) (305T) = 305 * 3660

Substitute 305T from (4)

**(610 + V)(1586 + 0.4V) = 305 * 3660**Clearly we got quadratic equation of V.

Simply the equation and we get-

**0.4 + 1830V - 150670 = 0**Using shridharacharya method

**V ≈ 83.87 miles/hr**