# An iron sphere of mass 10 kg is dropped from a height of 80 cm , if 'g' = 10cm/s² . Calculate the momentum transferred to the ground by the body . I need the answer with steps .....plsss.....fast...

2
by g2000

## Answers

2014-08-10T22:04:48+05:30

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M = 10 Kg
Velocity just before striking Earth = V
V² = u² + 2 g h
V² = 0² + 2 * 9.8m/sec² * 0.80 m
V = 3.96 m/sec

Momentum before striking earth = 10 kg * 3.96 m/sec = 39.6 kg m /sec
After collision, both the iron sphere and the earth have the same momentum. The total momentum is = 39.6 m/sec.

momentum conservation:
39.6  =  Momentum of ground + momentum of iron sphere
= (mass of ground + mass of iron sphere ) * velocity of both
= mass of ground * velocity of ground    as sphere is negligible as
compared to mass of ground.
Momentum transfered to ground = 39.6 kg m /sec

• Brainly User
2014-08-10T23:43:49+05:30
Velocity= 2gh^1/2= (2x10x80)^1/2=40cm/sec
hence  momenum transferred= massx velocity
p=10kgx40cm/sec=400kg-cm/s