Answers

2016-04-15T14:10:07+05:30
Hi! In right ΔOAB, BC = 3 and AC = 1 AB2 = BC2 + AC2 (Pythagoras theorem) = 32 + 12 = 9 +1 AB2 = 10 AB = √10 If BC is taken as any number other than 3, then the value of AB in that case would not be equal to √10. Cheers!
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