# An object of mass 3 kg is at rest.if a force F= (6t²i+4tj) N is applied on the object , then the velocity of the object at t=3 s is -------m/s.please explain with clear explanation..:-)

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now we integrate both sides with limits 0 to 3 to get the velocity

that gives us:(2t^3 + 2t^2)/m

putting the values we get the right answer

:)