# "find the perimeter and diagonal of a square whose area is equal to the area of a rectangle whose lengthis 9m and breadth is 4m."

2
by sayandeb

2014-08-11T17:10:13+05:30
Let the side o of square = x
a/q,
area of square = area of recangle
or,    = 9×4
or,  x =
therefore, x=6 m
we know that , perimeter of square = 4×x
perimeter of square = 4×6 =24 m
now, diagonal of square =
or, diagonal of square =
or, diagonal of square = ×x
or, diagonal of square = 6 m = 8.52 m
2014-08-11T18:20:55+05:30
Given,
Area of rectangle = Area of square
Area of rectangle = length × breadth
= 9 × 4
= 36m²
therefore,area of square = 36m²
w.k.t.Area of square = (side)²
= 36 = 6²
side = 6m
let the side be 'a'
a = 6
Perimeter of square = 4a
= 4×6 = 24m
Diagonal of the square = √2 a
= 6√2m
its better, thanks