# "find the perimeter and diagonal of a square whose area is equal to the area of a rectangle whose lengthis 9m and breadth is 4m."

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by sayandeb

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by sayandeb

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a/q,

area of square = area of recangle

or, = 9×4

or, x =

therefore, x=6 m

we know that , perimeter of square = 4×x

perimeter of square = 4×6 =24 m

now, diagonal of square =

or, diagonal of square =

or, diagonal of square = ×x

or, diagonal of square = 6 m = 8.52 m

Area of rectangle = Area of square

Area of rectangle = length × breadth

= 9 × 4

= 36m²

therefore,area of square = 36m²

w.k.t.Area of square = (side)²

= 36 = 6²

side = 6m

let the side be 'a'

a = 6

Perimeter of square = 4a

= 4×6 = 24m

Diagonal of the square = √2 a

= 6√2m