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## Answers

×2sinx.cosx

1+ = sin2x.

2-

after solving this equation,we get,_

sin2x = [tex] \frac{1}{4} and sin2x = -2

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×2sinx.cosx

1+ = sin2x.

2-

after solving this equation,we get,_

sin2x = [tex] \frac{1}{4} and sin2x = -2