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A battery of 12V is connected in series with R1(2ohms),

R2(3 ohms) and R3(1

ohm).What is the voltage drop across R2?

2
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R2(3 ohms) and R3(1

ohm).What is the voltage drop across R2?

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current i = 12/6 = 2 A

this current is same for all resistor

hence,voltage drop across 2 ohm = i*R2 = 2*2 = 4 volts

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