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## Answers

according to the sum,

x(x+1) = 3192

x(square) + x -3192=0

x(square) +57x - 56x - 3192 =0

x(x + 57) - 56(x + 57) =0

(x-56)(x + 57) =0

value of x= 56, -57

the required number, that is the smallest number is-56.

let the two numbers be x and x+1

so product is x(x+1)

given x(x+1)= 3192

x²+x-3192=0

x²+57x-56-x-3192=0

x(x+57)-56(x+57)=0

(x-56)(x+57)=0

the numbers are 56 and -57

since it is two positive integers -57 is not valid

so the numbers are 56 and 56+1