# Find the number whose tenth part increased by 10 is equal to its eighth part diminished by 10.

2
by son3

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by son3

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then,

x/10+10 = x/8-10

x+100/10=x-80/8

8(x+100)=10(x-80) .............(by cross multiplication)

8x+800=10x-800

8x-10x= -800-800

-2x= -1600

2x= 1600

x= 1600/2

x=800

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Let the no. be x...... ATQ.....x/10+10=x/8-10..............x/10-x/8=-10-10...............4x-5x/40= -20.......-1x/40=-20.......x=-20×40/-1( - sign gets cancelled).............x=800....