# Find the number whose tenth part increased by 10 is equal to its eighth part diminished by 10.

2
by son3

2016-04-17T13:40:01+05:30
Let the number be x.
then,
x/10+10 = x/8-10
x+100/10=x-80/8
8(x+100)=10(x-80)  .............(by cross multiplication)
8x+800=10x-800
8x-10x= -800-800
-2x= -1600
2x= 1600
x= 1600/2
x=800

thanks
thanks
thank you very much
hi son3
2016-04-17T13:49:26+05:30

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Let the no. be x...... ATQ.....x/10+10=x/8-10..............x/10-x/8=-10-10...............4x-5x/40= -20.......-1x/40=-20.......x=-20×40/-1( - sign gets cancelled).............x=800....
plz..buddies cool down we are not allowed to talk heree....otherise mod.will delete the answer
Ok.ok.... I only want to know that y he reported my ans.
i don't know that
ok bye for all except kumarishiwangi
Hmm. Bye