Answers

2016-04-23T11:20:37+05:30
Let,
In a right angled triangle ABC, angle B=90°
construction:- draw BD perpendicular to AC

proof:-
∆ABC~∆BDC
by B.P.T
BC/AC=DC/BC
BC²=AC×DC -- eq1

also, ∆ABC~∆ADB
by B.P.T
AB/AC=AD/AB
AB²=AC×AD-- eq2

so, add eq 1 and 2 AB²+BC²=(AC×DC)+ (AC×AD)

AB²+BC²=AC(DC+AD)
AB²+BC²=AC×AC

W.K.T, AC=AD+DC

SO, AB²+BC²=AC²

Hence proved

B.P.T= basic proportionality theorem

W.K.T= we know that

~ = is similar to




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