Answers

2014-08-11T23:01:23+05:30
Let a be the first term
and d be the common difference then,
nth term=a+(n-1)d
1th term=a+(1-1)d
2=a+0
a=2
20th term=a+(20-1)d
2+19d=59
19d=59-2
19d=57
d=57/19
d=3
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2014-08-12T16:14:26+05:30

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So given first term(a)= 2
given 20 th term = 59
so using formula
value nth term = a + (n - 1)d      where n = no. of terms
59 = 2 + (20 - 1)d
d = 57/19 
d = 3
so common difference = 3

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