Answers

2016-04-19T19:11:29+05:30
let q1 be quotient of first division and q2 be the quotient of second division, d be the divisor and let original number be num.
the 2 equations formed are:
1) num=d*q1+27
2)2*num=d*q2+3

multiplying equation-1 by 2 and equating the equations gives us
=>d*q2+3=2dq1+54

shifting the d term on one side and numbers on the other 
=>d*q2-2*q1=51

taking d common from the left side
=>d(q2-2q1)=51

=>d=51/q2-2*q1

so d can either be 51 or one of its factor(17 or 3).
since we have a reminder of 27 in one case d cannot be less than 27.
so divisor is 51.
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