Answers

2016-04-20T22:33:53+05:30
Let 5-2/7√3 be rational no.
therefore
5-2/7√3=p/q
(where p and q are co prime)
2/7√3=5-p/q
2/7√3=5q-p/q
√3=7(5q-p)/2q
here 7,5,2,q,and p are integers.
therefore 7(5q-p)/2q is rational
therefore √3 is rational no
but this contradicts the fact that √3 is irrational no
therefore 5-2/7√3 is irrational no.
hence proved
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