Answers

2016-04-21T07:14:12+05:30
Given
quadratic polynomial = (k-1) x²+k x+1
one of the zeroes = -3
⇒ (k-1) (-3)² +k(-3) +1 =0
⇒(k-1) 9 -3k +1 = 0
⇒9k -9 -3k +1 =0
⇒6k -8 = 0
⇒6k = 8
⇒ k = 8/6 = 4/3

 


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