Answers

2016-04-22T16:36:42+05:30
Kw of water = [H+][OH-]
10^-12 = [H+][OH-] at 100 degree C

Let us assume the concentration of H+ = x

Since each water molecule dissociate into one proton and one hydroxide ion.
i.e , the quantity or the concentration of these two ions will be equal in water.
[H+] = [OH-]

Therefore,
10^ -12 = x.x
10^ -12 = x²
x = 10^ -6

[H+] = [OH-] = 10^ -6
pH = log [H+] = log 10^ -6 = 6 log 10 = 6

So the answer is option (a) 6.0
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