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## Answers

tan75=tan(45+30)=tan45+tan30/1-tan45*tan60=√3+1/√3-1

sin²52=0.62

=2(cos58/sin32)-√3(cos38*sin52/tan15*tan75*tan60)

=2(cos(90-32)/sin32)-√3(cos(90-52)*sin52/√3-1/√3+1*√3+1/√3-1*√3)

=2(sin32/sin32)-√3(sin52*sin52/√3)

=2(1)-√3(sin²52)

=2-√3(0.62/√3)

=2-(0.62)

=2-0.62

=1.32

The Brainliest Answer!

= 2{cos58/sin(90-58)}-√3[{cos38*cosec(90-38)}/tan(90-75)*tan60*tan75]

= 2{cos58/cos58}-√3[cos38*sec38/cot75*tan60*tan75] (1/tanФ = cotФ)

= 2*1-√3[1/tan60]

= 2-√3(1/√3)

= 2-1

= 1