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Find p(0),p(1) and P(2) for each of the polynomials

1}. p(y)=y²-y+1

2}. p(t) = 2 = t- 2t² - t³

3}. p(x) = (x-1) (x+1)

4}. p(x) = x²

1
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1}. p(y)=y²-y+1

2}. p(t) = 2 = t- 2t² - t³

3}. p(x) = (x-1) (x+1)

4}. p(x) = x²

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(i) p(y) = y² - y +1

p(0) = 0² - 0 +1

= 1

p(1) = 1² -1 +1

= 1

p(2) = 2² - 2 +1

= 3

(ii) p(t) = 2-t - 2t³-t³

p(0) = 0

p(1) = -2

p(2) = -16

(iii) p(x) =(x-1)(x+1)

p(0) = -1

p(1) = 0

p(2) = 3

(iv) p(x)= x²

p(0) = 0

p(1) = 1

p(2) =4