Answers

2016-04-24T12:30:54+05:30
Let required no of pounds of chocolates($1.10 a pound) be x.
∴The no of pounds of chocolates worth 90¢ a pound is (30-x).

∴1.5*x+0.9*(30-x) = 1.1*30  [ ∵Total price of the mixture =
$(1.1*30)]
   Solving, we get,
   x=10

∴Required no of chocolates
worth $1.50 a pound is 10 pounds.(Ans.)


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