# If a bus travelling at 20 m/s is subjected to a steady deceleration of 5 m/s2,how long will it take to come to the rest ?

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U=20m/s

a= -5m/s^2

v=0m/s

t=?

we know,

v=u+at

so,

0=20-5t

hence,

t=4 seconds

a= -5m/s^2

v=0m/s

t=?

we know,

v=u+at

so,

0=20-5t

hence,

t=4 seconds

Initial Velocity, u = 20 m/s

Final Velocity, v = 0 m/s

Acceleration, a = -5m/s² (minus sign because of deceleration)

Time, t = (?)

We know that,

a = (v - u)/t

∴t = (v - u)/a

∴t = (0 - 20)/(-5)

∴t = (-20)/(-5)

∴

Thus, the bus will take 4 seconds to stop.