# In a deer park the number of heads and the number of legs of deer and visitors were counted and it was found that there were 39 heads and 132 legs. Find the number of deers and visitors in the park, using graphical method.

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Let deer be represented by d and visitors represented by v.

deer and visitors have one head each, so d + v = 39

a deer has 4 legs and a visitor has 2 legs, so 4d + 2v = 132

d + v = 39

4d + 2v = 132

d = 39 - v

4(39 - v) + 2v = 132

156 - 4v +2v = 132

-2v = 132 - 156

-2v = -24

v = -24/-2

v = 12

d = 39 - v

d = 39 - 12

d = 27

there are 12 visitors and 27 deer.

to check:

d + v = 39

27 + 12 = 39

39 = 39

4d + 2v = 132

4(27) + 2(12) = 132

108 + 24 = 132

132 = 132

deer and visitors have one head each, so d + v = 39

a deer has 4 legs and a visitor has 2 legs, so 4d + 2v = 132

d + v = 39

4d + 2v = 132

d = 39 - v

4(39 - v) + 2v = 132

156 - 4v +2v = 132

-2v = 132 - 156

-2v = -24

v = -24/-2

v = 12

d = 39 - v

d = 39 - 12

d = 27

there are 12 visitors and 27 deer.

to check:

d + v = 39

27 + 12 = 39

39 = 39

4d + 2v = 132

4(27) + 2(12) = 132

108 + 24 = 132

132 = 132