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2016-05-03T16:48:05+05:30

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Let the positive charge be on the left side of negative charge.

Electric field to the left of the positive charge, along the line joining the two charges:

          E =  (1/4π∈)  [ q1 / d1²  +  q2 /d2² ]
              =  9 * 10⁹ * 10 * 10⁻⁶ [ 1/1² - 1/2² ]   Newt/Coul
              =  6.35 * 10⁴  Newt/Coul
            direction towards left away from the two charges.

Electric field at 1 meter away from negative charge on the right of it along the line joining them.

       E =  same magnitude .. same steps as above..
           direction is towards left side towards the negative charge.

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