# Ahmed and Ali were camel-drivers who wanted to become shepherds. So they went to the market and sold all their camels. The amount of money (in dinars) that they received for each camel was the same as the total number of camels they owned. With that money, they bought as many sheep as possible at 10 dinars a sheep. With the money that was left they bought a goat.On their way home they got in a fight and decided to split up. When they divided the sheep there was one sheep left. So Ali said to Ahmed, "I take the last sheep and you can get the goat"."That's not fair," said Ahmed, "a goat costs less than a sheep"."OK," Ali said, "then I will give you one of my dogs and then we are even".Ahmed agreed that the trade was fair. (since 1 sheep - 1 dog = 1 goat + 1 dog)What's the cost (in dinars) of a dog?

1
by Deleted account

2014-02-28T13:18:20+05:30
1 sheep - 1 dog = 1 goat + 1 dog
1 sheep - 1 goat = 2 dogs
as you question one sheep is 10 dinars, but the goat’s cost?
The ultimate money they get from the camel is a squre. And the number in the place of tens of the square is odd (total money / 10 dinars), for the reason that they couldn’t devide the sheep equally..
Now every squares by an odd tens close with a 6. (16^2 = 256 and 24^2 = 576). So a goat should charge 6 dinars.
10 - 6 = 2 dogs
So a dog costs 2 dinars

why could the amount be 36 or 49
36=3(10)+6
49=4(10)+9