# The additive inverse of a number, divided by twelve is the same as one less than three times its reciprocal. Find the number

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by charlotteds9

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by charlotteds9

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Let the required number = x

according to the question,

additive inverse of the number = -x

condition : -x/12 = 3/x -1

-x/12 = (3-x)/ x

- x² = 36 - 12x

x² - 12x +36 = 0

x ² -6x- 6x + 36 =0

x(x - 6) - 6( x - 6) = 0

(x-6)(x-6) = 0

x = 6

therefore , the number is 6.

according to the question,

additive inverse of the number = -x

condition : -x/12 = 3/x -1

-x/12 = (3-x)/ x

- x² = 36 - 12x

x² - 12x +36 = 0

x ² -6x- 6x + 36 =0

x(x - 6) - 6( x - 6) = 0

(x-6)(x-6) = 0

x = 6

therefore , the number is 6.