# The brakes applied to a car produce a negative acceleration of 10m/sec. If the car takes 5sec to stop after applying brakes. Calculate distance covered by a car before coming to rest

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by Kshitu1

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by Kshitu1

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t = 5 sec

v = 0 m/s

v= u +at

⇒ 0 = u + (-10)×5

⇒u = 50 m/s

now, s = ut + (1/2)at²

= 50×5 + (1/2)×(-10)×(5)²

= 250 -125 =