Answers

2016-04-29T12:14:44+05:30
a+b+c = 0, a4+b4+c4 = 2a2b2+2b2c2+2c2a2
a+b+c = 0
a+b = -c
(a+b )2 = (-c)2
a2+b2+2ab = c2​   
(a+b )2=a2+b2+2ab //
a2+b2- c2​ = 2ab  
(a2+b2- c2​ )2= (2ab ) 2 
(a4+b4+ c4​+2a2b2-2b2c2-2c2a2)  =4a2b2  
a4+b4+ c4​+2a2b2-4a2b2-2b2c2-2c2a2 = 0
a4+b4+ c4​-2a2b2-2b2c2-2c2a2 = 0
a4+b4+ c4​ = 2a2b2+2b2c2+2c2a2




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