Answers

2016-04-30T09:31:36+05:30
It is given that on dividing 546 and 764 we will get the remainder 6 and 8 respectively

this means, 546 - 6 = 540
and              764 - 8 = 756
are completely divisible by the required no.

so now we will find the HCF

( You can find the hcf by Euclid's didvision lemma or by prime factorization)

540 = 2² × 3³  × 5
756  = 2²×3³×7

so the hcf or the required no. is 2 × 2 ×3×3×3 = 108
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2016-04-30T10:47:30+05:30
It is given that on dividing 546 and 764 we will get the remainder 6 and 8 respectively this means, 546 - 6 = 540 and 764 - 8 = 756 are completely divisible by the required no. so now we will find the HCF ( You can find the hcf by Euclid's didvision lemma or by prime factorization) 540 = 2² × 3³ × 5 756 = 2²×3³×7
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